x^2+1.80x+0.109=0

Solution for x^2+1.80x+0.109=0 equation:

x^2+1.80x+0.109=0

a = 1; b = 1.80; c = +0.109;
Δ = b2-4ac
Δ = 1.802-4·1·0.109
Δ = 2.804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.80)-\sqrt{2.804}}{2*1}=\frac{-1.8-\sqrt{2.804}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.80)+\sqrt{2.804}}{2*1}=\frac{-1.8+\sqrt{2.804}}{2}
$